(2x+1)(x^2-x-1)=0

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Solution for (2x+1)(x^2-x-1)=0 equation: 


Simplifying
(2x + 1)(x2 + -1x + -1) = 0

Reorder the terms:
(1 + 2x)(x2 + -1x + -1) = 0

Reorder the terms:
(1 + 2x)(-1 + -1x + x2) = 0

Multiply (1 + 2x) * (-1 + -1x + x2)
(1(-1 + -1x + x2) + 2x * (-1 + -1x + x2)) = 0
((-1 * 1 + -1x * 1 + x2 * 1) + 2x * (-1 + -1x + x2)) = 0
((-1 + -1x + 1x2) + 2x * (-1 + -1x + x2)) = 0
(-1 + -1x + 1x2 + (-1 * 2x + -1x * 2x + x2 * 2x)) = 0
(-1 + -1x + 1x2 + (-2x + -2x2 + 2x3)) = 0

Reorder the terms:
(-1 + -1x + -2x + 1x2 + -2x2 + 2x3) = 0

Combine like terms: -1x + -2x = -3x
(-1 + -3x + 1x2 + -2x2 + 2x3) = 0

Combine like terms: 1x2 + -2x2 = -1x2
(-1 + -3x + -1x2 + 2x3) = 0

Solving
-1 + -3x + -1x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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